Question

$$\frac{3}{(x+2)}-\frac{1}{x}=\frac{y}{15}$$

Solve for y

$y=\frac{30\left(x-1\right)}{x\left(x+2\right)}$
$x\neq -2\text{ and }x\neq 0$

Show Solution

Solve for x (complex solution)

$\left\{\begin{matrix}x=-\frac{\sqrt{y^{2}-60y+225}+y-15}{y}\text{; }x=-\frac{-\sqrt{y^{2}-60y+225}+y-15}{y}\text{, }&y\neq 0\\x=1\text{, }&y=0\end{matrix}\right.$

Solve for x

$\left\{\begin{matrix}x=-\frac{\sqrt{y^{2}-60y+225}+y-15}{y}\text{; }x=-\frac{-\sqrt{y^{2}-60y+225}+y-15}{y}\text{, }&\left(y\neq 0\text{ and }y\leq 30-15\sqrt{3}\right)\text{ or }y\geq 15\sqrt{3}+30\\x=1\text{, }&y=0\end{matrix}\right.$