$$\frac{3}{x}+\frac{2}{y}=\frac{19}{20}$$
$x=-\frac{60y}{40-19y}$
$y\neq 0\text{ and }y\neq \frac{40}{19}$
$y=-\frac{40x}{60-19x}$
$x\neq 0\text{ and }x\neq \frac{60}{19}$