Question

$$\frac{3}{x}+\frac{2}{y}=\frac{19}{20}$$

Solve for x

$x=-\frac{60y}{40-19y}$
$y\neq 0\text{ and }y\neq \frac{40}{19}$

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Solve for y

$y=-\frac{40x}{60-19x}$
$x\neq 0\text{ and }x\neq \frac{60}{19}$

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