$$\frac{3-i}{i-3i}$$
$\frac{1}{2}+\frac{3}{2}i=0.5+1.5i$
$$\frac{3-i}{-2i}$$
$$\frac{\left(3-i\right)i}{-2i^{2}}$$
$$\frac{\left(3-i\right)i}{2}$$
$$\frac{3i-i^{2}}{2}$$
$$\frac{3i-\left(-1\right)}{2}$$
$$\frac{1+3i}{2}$$
$$\frac{1}{2}+\frac{3}{2}i$$
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$\frac{1}{2} = 0.5$
$$Re(\frac{3-i}{-2i})$$
$$Re(\frac{\left(3-i\right)i}{-2i^{2}})$$
$$Re(\frac{\left(3-i\right)i}{2})$$
$$Re(\frac{3i-i^{2}}{2})$$
$$Re(\frac{3i-\left(-1\right)}{2})$$
$$Re(\frac{1+3i}{2})$$
$$Re(\frac{1}{2}+\frac{3}{2}i)$$
$$\frac{1}{2}$$
