$$\frac{3+-2}{4}-\frac{2++3}{3}=\frac{2}{3}$$
$\text{false}$
$$3\left(3-2\right)-4\left(2+3\right)=8$$
$$3\times 1-4\left(2+3\right)=8$$
$$3-4\left(2+3\right)=8$$
$$3-4\times 5=8$$
$$3-20=8$$
$$-17=8$$
$$\text{false}$$
Show Solution
Hide Solution
