Question

$$\frac{3^{n+3}-3\times3^{n}}{4\times3^{n+3}}$$

Answer

$$(3^(n+3)-3^(1+n))/(4*3^(n+3))$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\frac{{3}^{n+3}-{3}^{1+n}}{4\times {3}^{n+3}}\]