Factor $148=2^{2}\times 37$. Rewrite the square root of the product $\sqrt{2^{2}\times 37}$ as the product of square roots $\sqrt{2^{2}}\sqrt{37}$. Take the square root of $2^{2}$.
$$\frac{3\times 2\sqrt{37}}{3333333}$$
Multiply $3$ and $2$ to get $6$.
$$\frac{6\sqrt{37}}{3333333}$$
Divide $6\sqrt{37}$ by $3333333$ to get $\frac{2}{1111111}\sqrt{37}$.
