How to solve 32/12 + 1/6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 32/12 + 1/6 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

$$\frac{32}{12}+\frac{1}{6}$$

$\frac{17}{6}\approx 2.833333333$

Reduce the fraction $\frac{32}{12}$ to lowest terms by extracting and canceling out $4$.

$$\frac{8}{3}+\frac{1}{6}$$

Least common multiple of $3$ and $6$ is $6$. Convert $\frac{8}{3}$ and $\frac{1}{6}$ to fractions with denominator $6$.

$$\frac{16}{6}+\frac{1}{6}$$

Since $\frac{16}{6}$ and $\frac{1}{6}$ have the same denominator, add them by adding their numerators.

$$\frac{16+1}{6}$$

Add $16$ and $1$ to get $17$.

$$\frac{17}{6}$$

$\frac{17}{2 \cdot 3} = 2\frac{5}{6} = 2.8333333333333335$