How to solve 32/(20 - 9 1/3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 32/(20 - 9 1/3) | Equatix

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3(r+2s)=2t-4

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Question

$$\frac{32}{20-9\frac{1}{3}}$$

Evaluate

$3$

Solution Steps

Multiply $9$ and $3$ to get $27$.

$$\frac{32}{20-\frac{27+1}{3}}$$

Add $27$ and $1$ to get $28$.

$$\frac{32}{20-\frac{28}{3}}$$

Convert $20$ to fraction $\frac{60}{3}$.

$$\frac{32}{\frac{60}{3}-\frac{28}{3}}$$

Since $\frac{60}{3}$ and $\frac{28}{3}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{32}{\frac{60-28}{3}}$$

Subtract $28$ from $60$ to get $32$.

$$\frac{32}{\frac{32}{3}}$$

Divide $32$ by $\frac{32}{3}$ by multiplying $32$ by the reciprocal of $\frac{32}{3}$.

$$32\times \frac{3}{32}$$

Cancel out $32$ and $32$.

$$3$$

Show Solution

Factor

$3$

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