How to solve 32/3 - 58/9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 32/3 - 58/9 | Equatix

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$$\frac{32}{3}-\frac{58}{9}$$

$\frac{38}{9}\approx 4.222222222$

Least common multiple of $3$ and $9$ is $9$. Convert $\frac{32}{3}$ and $\frac{58}{9}$ to fractions with denominator $9$.

$$\frac{96}{9}-\frac{58}{9}$$

Since $\frac{96}{9}$ and $\frac{58}{9}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{96-58}{9}$$

Subtract $58$ from $96$ to get $38$.

$$\frac{38}{9}$$

$\frac{2 \cdot 19}{3 ^ {2}} = 4\frac{2}{9} = 4.222222222222222$