How to solve by using BODMAS

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$\frac { 34 } { 99 } + 4 \frac { 7 } { 33 } - 5 \frac { 9 } { 11 }$$

Evaluate

$-\frac{125}{99}\approx -1.262626263$

Solution Steps

Multiply $4$ and $33$ to get $132$.

$$\frac{34}{99}+\frac{132+7}{33}-\frac{5\times 11+9}{11}$$

Add $132$ and $7$ to get $139$.

$$\frac{34}{99}+\frac{139}{33}-\frac{5\times 11+9}{11}$$

Least common multiple of $99$ and $33$ is $99$. Convert $\frac{34}{99}$ and $\frac{139}{33}$ to fractions with denominator $99$.

$$\frac{34}{99}+\frac{417}{99}-\frac{5\times 11+9}{11}$$

Since $\frac{34}{99}$ and $\frac{417}{99}$ have the same denominator, add them by adding their numerators.

$$\frac{34+417}{99}-\frac{5\times 11+9}{11}$$

Add $34$ and $417$ to get $451$.

$$\frac{451}{99}-\frac{5\times 11+9}{11}$$

Reduce the fraction $\frac{451}{99}$ to lowest terms by extracting and canceling out $11$.

$$\frac{41}{9}-\frac{5\times 11+9}{11}$$

Multiply $5$ and $11$ to get $55$.

$$\frac{41}{9}-\frac{55+9}{11}$$

Add $55$ and $9$ to get $64$.

$$\frac{41}{9}-\frac{64}{11}$$

Least common multiple of $9$ and $11$ is $99$. Convert $\frac{41}{9}$ and $\frac{64}{11}$ to fractions with denominator $99$.

$$\frac{451}{99}-\frac{576}{99}$$

Since $\frac{451}{99}$ and $\frac{576}{99}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{451-576}{99}$$

Subtract $576$ from $451$ to get $-125$.

$$-\frac{125}{99}$$

Show Solution

Factor

$-\frac{125}{99} = -1\frac{26}{99} = -1.2626262626262625$