How to solve 37/3 / (9/4) =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 37/3 / (9/4) = | Equatix

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$$\frac{37}{3}\div\frac{9}{4}=$$

$\frac{148}{27}\approx 5.481481481$

Divide $\frac{37}{3}$ by $\frac{9}{4}$ by multiplying $\frac{37}{3}$ by the reciprocal of $\frac{9}{4}$.

$$\frac{37}{3}\times \frac{4}{9}$$

Multiply $\frac{37}{3}$ times $\frac{4}{9}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{37\times 4}{3\times 9}$$

Do the multiplications in the fraction $\frac{37\times 4}{3\times 9}$.

$$\frac{148}{27}$$

$\frac{2 ^ {2} \cdot 37}{3 ^ {3}} = 5\frac{13}{27} = 5.481481481481482$