How to solve 37/3 + 9/4 =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 37/3 + 9/4 = | Equatix

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$$\frac{37}{3}+\frac{9}{4}=$$

$\frac{175}{12}\approx 14.583333333$

Least common multiple of $3$ and $4$ is $12$. Convert $\frac{37}{3}$ and $\frac{9}{4}$ to fractions with denominator $12$.

$$\frac{148}{12}+\frac{27}{12}$$

Since $\frac{148}{12}$ and $\frac{27}{12}$ have the same denominator, add them by adding their numerators.

$$\frac{148+27}{12}$$

Add $148$ and $27$ to get $175$.

$$\frac{175}{12}$$

$\frac{5 ^ {2} \cdot 7}{2 ^ {2} \cdot 3} = 14\frac{7}{12} = 14.583333333333334$