How to solve (3n)/(4n-5)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (3n)/(4n-5) | Equatix

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Question

$$\frac{ 3n }{ 4n-5 }$$

Differentiate w.r.t. n

$-\frac{15}{\left(4n-5\right)^{2}}$

Steps Using Derivative Rule for Quotient

For any two differentiable functions, the derivative of the quotient of two functions is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the denominator squared.

$$\frac{\left(4n^{1}-5\right)\frac{\mathrm{d}}{\mathrm{d}n}(3n^{1})-3n^{1}\frac{\mathrm{d}}{\mathrm{d}n}(4n^{1}-5)}{\left(4n^{1}-5\right)^{2}}$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$\frac{\left(4n^{1}-5\right)\times 3n^{1-1}-3n^{1}\times 4n^{1-1}}{\left(4n^{1}-5\right)^{2}}$$

Do the arithmetic.

$$\frac{\left(4n^{1}-5\right)\times 3n^{0}-3n^{1}\times 4n^{0}}{\left(4n^{1}-5\right)^{2}}$$

Expand using distributive property.

$$\frac{4n^{1}\times 3n^{0}-5\times 3n^{0}-3n^{1}\times 4n^{0}}{\left(4n^{1}-5\right)^{2}}$$

To multiply powers of the same base, add their exponents.

$$\frac{4\times 3n^{1}-5\times 3n^{0}-3\times 4n^{1}}{\left(4n^{1}-5\right)^{2}}$$

Do the arithmetic.

$$\frac{12n^{1}-15n^{0}-12n^{1}}{\left(4n^{1}-5\right)^{2}}$$

Combine like terms.

$$\frac{\left(12-12\right)n^{1}-15n^{0}}{\left(4n^{1}-5\right)^{2}}$$

Subtract $12$ from $12$.

$$\frac{-15n^{0}}{\left(4n^{1}-5\right)^{2}}$$

For any term $t$, $t^{1}=t$.

$$\frac{-15n^{0}}{\left(4n-5\right)^{2}}$$

For any term $t$ except $0$, $t^{0}=1$.

$$\frac{-15}{\left(4n-5\right)^{2}}$$

Show Solution

Evaluate

$\frac{3n}{4n-5}$