$$\frac{3t-2}{4}-\frac{2t+3}{3}=\frac{2}{3}-1$$
$t=14$
$$3\left(3t-2\right)-4\left(2t+3\right)=8-12$$
$$9t-6-4\left(2t+3\right)=8-12$$
$$9t-6-8t-12=8-12$$
$$t-6-12=8-12$$
$$t-18=8-12$$
$$t-18=-4$$
$$t=-4+18$$
$$t=14$$
Show Solution
Hide Solution