Question

$$\frac{3t-2}{4}-\frac{2t+3}{3}-\frac{2}{3}-t; (2t+3)$$

Answer

(3*t-2)/4-(2*t+3)/3-2/3-t;2*t+3

Solution


Remove parentheses.
\[\begin{aligned}&\frac{3t-2}{4}-\frac{2t+3}{3}-\frac{2}{3}-t\\&2t+3\end{aligned}\]