$$\frac{3t-2}{4}-(\frac{2t+3}{3})=\frac{2}{3}t$$
$t = -\frac{18}{7} = -2\frac{4}{7} \approx -2.571428571$
$$3\left(3t-2\right)-4\left(2t+3\right)=8t$$
$$9t-6-4\left(2t+3\right)=8t$$
$$9t-6-8t-12=8t$$
$$t-6-12=8t$$
$$t-18=8t$$
$$t-18-8t=0$$
$$-7t-18=0$$
$$-7t=18$$
$$t=\frac{18}{-7}$$
$$t=-\frac{18}{7}$$
Show Solution
Hide Solution
