$$\frac{ 3x+1 }{ (x+4)(x+3) }$$
$\frac{3x+1}{\left(x+3\right)\left(x+4\right)}$
$$\frac{3x+1}{x^{2}+3x+4x+12}$$
$$\frac{3x+1}{x^{2}+7x+12}$$
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