$$\frac{3x+4}{2}-\frac{4x-1}{3}=\frac{x+12}{4}$$
$x=-8$
$$6\left(3x+4\right)-4\left(4x-1\right)=3\left(x+12\right)$$
$$18x+24-4\left(4x-1\right)=3\left(x+12\right)$$
$$18x+24-16x+4=3\left(x+12\right)$$
$$2x+24+4=3\left(x+12\right)$$
$$2x+28=3\left(x+12\right)$$
$$2x+28=3x+36$$
$$2x+28-3x=36$$
$$-x+28=36$$
$$-x=36-28$$
$$-x=8$$
$$x=-8$$
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