Question

$$\frac{3x^{2}+12x+12=0}{3}$$

Answer

x=-1,-3

Solution


Move all terms to one side.
\[3{x}^{2}+12x+12-03=0\]
Simplify  \(3{x}^{2}+12x+12-03\)  to  \(3{x}^{2}+12x+9\).
\[3{x}^{2}+12x+9=0\]
Factor out the common term \(3\).
\[3({x}^{2}+4x+3)=0\]
Factor \({x}^{2}+4x+3\).
\[3(x+1)(x+3)=0\]
Solve for \(x\).
\[x=-1,-3\]