$$\frac{ 3y-5 }{ 2 } - \frac{ 4y+5 }{ } = \frac{ 3 }{ 4 } +y$$
$y = -\frac{33}{14} = -2\frac{5}{14} \approx -2.357142857$
$$2\left(3y-5\right)-4\left(4y+5\right)=3+4y$$
$$6y-10-4\left(4y+5\right)=3+4y$$
$$6y-10-16y-20=3+4y$$
$$-10y-10-20=3+4y$$
$$-10y-30=3+4y$$
$$-10y-30-4y=3$$
$$-14y-30=3$$
$$-14y=3+30$$
$$-14y=33$$
$$y=\frac{33}{-14}$$
$$y=-\frac{33}{14}$$
Show Solution
Hide Solution