$$\frac{3y+1}{5}=\frac{3y-7}{3}$$
$y = \frac{19}{3} = 6\frac{1}{3} \approx 6.333333333$
$$3\left(3y+1\right)=5\left(3y-7\right)$$
$$9y+3=5\left(3y-7\right)$$
$$9y+3=15y-35$$
$$9y+3-15y=-35$$
$$-6y+3=-35$$
$$-6y=-35-3$$
$$-6y=-38$$
$$y=\frac{-38}{-6}$$
$$y=\frac{19}{3}$$
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