Question

$$\frac{4}{13}=\frac{x}{20,4-k}$$

Solve for x

$x=-\frac{4k}{13}+\frac{408}{65}$
$k\neq \frac{102}{5}$

Show Solution

Solve for k

$k=-\frac{13x}{4}+20,4$
$x\neq 0$