How to solve 4/15 + 17/(2!)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4/15 + 17/(2!) | Equatix

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$$\frac { 4 } { 15 } + \frac { 1 } { 2 }$$

$\frac{23}{30}\approx 0.766666667$

Least common multiple of $15$ and $2$ is $30$. Convert $\frac{4}{15}$ and $\frac{1}{2}$ to fractions with denominator $30$.

$$\frac{8}{30}+\frac{15}{30}$$

Since $\frac{8}{30}$ and $\frac{15}{30}$ have the same denominator, add them by adding their numerators.

$$\frac{8+15}{30}$$

Add $8$ and $15$ to get $23$.

$$\frac{23}{30}$$

$\frac{23}{2 \cdot 3 \cdot 5} = 0.7666666666666667$