Solve (4)/(16)+(5)/(20)+(7)/(14)= | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac{ 4 }{ 16 } + \frac{ 5 }{ 20 } + \frac{ 7 }{ 14 } =$$

Evaluate

$1$

Solution Steps

Reduce the fraction $\frac{4}{16}$ to lowest terms by extracting and canceling out $4$.

$$\frac{1}{4}+\frac{5}{20}+\frac{7}{14}$$

Reduce the fraction $\frac{5}{20}$ to lowest terms by extracting and canceling out $5$.

$$\frac{1}{4}+\frac{1}{4}+\frac{7}{14}$$

Since $\frac{1}{4}$ and $\frac{1}{4}$ have the same denominator, add them by adding their numerators.

$$\frac{1+1}{4}+\frac{7}{14}$$

Add $1$ and $1$ to get $2$.

$$\frac{2}{4}+\frac{7}{14}$$

Reduce the fraction $\frac{2}{4}$ to lowest terms by extracting and canceling out $2$.

$$\frac{1}{2}+\frac{7}{14}$$

Reduce the fraction $\frac{7}{14}$ to lowest terms by extracting and canceling out $7$.

$$\frac{1}{2}+\frac{1}{2}$$

Since $\frac{1}{2}$ and $\frac{1}{2}$ have the same denominator, add them by adding their numerators.

$$\frac{1+1}{2}$$

Add $1$ and $1$ to get $2$.

$$\frac{2}{2}$$

Divide $2$ by $2$ to get $1$.

$$1$$

Factor

$1$