$$\frac{ 4 }{ 3 } + \frac{ 4 }{ 3 } \times \frac{ 1 }{ 3 } + \frac{ 1 }{ 3 }$$
$\frac{19}{9}\approx 2.111111111$
$$\frac{4}{3}+\frac{4\times 1}{3\times 3}+\frac{1}{3}$$
$$\frac{4}{3}+\frac{4}{9}+\frac{1}{3}$$
$$\frac{12}{9}+\frac{4}{9}+\frac{1}{3}$$
$$\frac{12+4}{9}+\frac{1}{3}$$
$$\frac{16}{9}+\frac{1}{3}$$
$$\frac{16}{9}+\frac{3}{9}$$
$$\frac{16+3}{9}$$
$$\frac{19}{9}$$
Show Solution
Hide Solution
$\frac{19}{3 ^ {2}} = 2\frac{1}{9} = 2.111111111111111$
