1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$\frac { 4 } { 5 } - ( \frac { - 3 } { 4 } ) + ( \frac { - 8 } { 11 } ) - 1$$

Evaluate

$-\frac{39}{220}\approx -0.177272727$

Solution Steps

Fraction $\frac{-3}{4}$ can be rewritten as $-\frac{3}{4}$ by extracting the negative sign.

$$\frac{4}{5}-\left(-\frac{3}{4}\right)+\frac{-8}{11}-1$$

The opposite of $-\frac{3}{4}$ is $\frac{3}{4}$.

$$\frac{4}{5}+\frac{3}{4}+\frac{-8}{11}-1$$

Least common multiple of $5$ and $4$ is $20$. Convert $\frac{4}{5}$ and $\frac{3}{4}$ to fractions with denominator $20$.

$$\frac{16}{20}+\frac{15}{20}+\frac{-8}{11}-1$$

Since $\frac{16}{20}$ and $\frac{15}{20}$ have the same denominator, add them by adding their numerators.

$$\frac{16+15}{20}+\frac{-8}{11}-1$$

Add $16$ and $15$ to get $31$.

$$\frac{31}{20}+\frac{-8}{11}-1$$

Fraction $\frac{-8}{11}$ can be rewritten as $-\frac{8}{11}$ by extracting the negative sign.

$$\frac{31}{20}-\frac{8}{11}-1$$

Least common multiple of $20$ and $11$ is $220$. Convert $\frac{31}{20}$ and $\frac{8}{11}$ to fractions with denominator $220$.

$$\frac{341}{220}-\frac{160}{220}-1$$

Since $\frac{341}{220}$ and $\frac{160}{220}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{341-160}{220}-1$$

Subtract $160$ from $341$ to get $181$.

$$\frac{181}{220}-1$$

Convert $1$ to fraction $\frac{220}{220}$.

$$\frac{181}{220}-\frac{220}{220}$$

Since $\frac{181}{220}$ and $\frac{220}{220}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{181-220}{220}$$

Subtract $220$ from $181$ to get $-39$.

$$-\frac{39}{220}$$

Show Solution

Factor

$-\frac{39}{220} = -0.17727272727272728$