How to solve 4/5 + 7/3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4/5 + 7/3 | Equatix

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$$\frac{4}{5}+\frac{7}{3}$$

$\frac{47}{15}\approx 3.133333333$

Least common multiple of $5$ and $3$ is $15$. Convert $\frac{4}{5}$ and $\frac{7}{3}$ to fractions with denominator $15$.

$$\frac{12}{15}+\frac{35}{15}$$

Since $\frac{12}{15}$ and $\frac{35}{15}$ have the same denominator, add them by adding their numerators.

$$\frac{12+35}{15}$$

Add $12$ and $35$ to get $47$.

$$\frac{47}{15}$$

$\frac{47}{3 \cdot 5} = 3\frac{2}{15} = 3.1333333333333333$