1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4/6 = 5 | Equatix

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a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac{4}{6}=5$$

Verify

$\text{false}$

Solution Steps

Reduce the fraction $\frac{4}{6}$ to lowest terms by extracting and canceling out $2$.

$$\frac{2}{3}=5$$

Convert $5$ to fraction $\frac{15}{3}$.

$$\frac{2}{3}=\frac{15}{3}$$

Compare $\frac{2}{3}$ and $\frac{15}{3}$.

$$\text{false}$$

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