How to solve 4/6 + 7/4 + 3/4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4/6 + 7/4 + 3/4 | Equatix

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Question

$$\frac{4}{6}+\frac{7}{4}+\frac{3}{4}$$

Evaluate

$\frac{19}{6}\approx 3.166666667$

Solution Steps

Reduce the fraction $\frac{4}{6}$ to lowest terms by extracting and canceling out $2$.

$$\frac{2}{3}+\frac{7}{4}+\frac{3}{4}$$

Least common multiple of $3$ and $4$ is $12$. Convert $\frac{2}{3}$ and $\frac{7}{4}$ to fractions with denominator $12$.

$$\frac{8}{12}+\frac{21}{12}+\frac{3}{4}$$

Since $\frac{8}{12}$ and $\frac{21}{12}$ have the same denominator, add them by adding their numerators.

$$\frac{8+21}{12}+\frac{3}{4}$$

Add $8$ and $21$ to get $29$.

$$\frac{29}{12}+\frac{3}{4}$$

Least common multiple of $12$ and $4$ is $12$. Convert $\frac{29}{12}$ and $\frac{3}{4}$ to fractions with denominator $12$.

$$\frac{29}{12}+\frac{9}{12}$$

Since $\frac{29}{12}$ and $\frac{9}{12}$ have the same denominator, add them by adding their numerators.

$$\frac{29+9}{12}$$

Add $29$ and $9$ to get $38$.

$$\frac{38}{12}$$

Reduce the fraction $\frac{38}{12}$ to lowest terms by extracting and canceling out $2$.

$$\frac{19}{6}$$

Show Solution

Factor

$\frac{19}{2 \cdot 3} = 3\frac{1}{6} = 3.1666666666666665$