$$\frac{4}{6}+\frac{8}{4}+(\frac{-4}{5})+(\frac{-4}{6})$$
$\frac{6}{5}=1.2$
$$\frac{2}{3}+\frac{8}{4}+\frac{-4}{5}+\frac{-4}{6}$$
$$\frac{2}{3}+2+\frac{-4}{5}+\frac{-4}{6}$$
$$\frac{2}{3}+\frac{6}{3}+\frac{-4}{5}+\frac{-4}{6}$$
$$\frac{2+6}{3}+\frac{-4}{5}+\frac{-4}{6}$$
$$\frac{8}{3}+\frac{-4}{5}+\frac{-4}{6}$$
$$\frac{8}{3}-\frac{4}{5}+\frac{-4}{6}$$
$$\frac{40}{15}-\frac{12}{15}+\frac{-4}{6}$$
$$\frac{40-12}{15}+\frac{-4}{6}$$
$$\frac{28}{15}+\frac{-4}{6}$$
$$\frac{28}{15}-\frac{2}{3}$$
$$\frac{28}{15}-\frac{10}{15}$$
$$\frac{28-10}{15}$$
$$\frac{18}{15}$$
$$\frac{6}{5}$$
Show Solution
Hide Solution
$\frac{2 \cdot 3}{5} = 1\frac{1}{5} = 1.2$
