$$\frac{4}{7}\times[(\frac{-6}{13})+(\frac{-3}{17})]=\frac{4}{7}\times(\frac{-6}{13})]; +\lfloor\frac{4}{7}\times(\frac{-3}{17})\rfloor$$
$\text{false}$
$$\frac{-6}{13}+\frac{-3}{17}=\frac{-6}{13}$$
$$-\frac{6}{13}+\frac{-3}{17}=\frac{-6}{13}$$
$$-\frac{6}{13}-\frac{3}{17}=\frac{-6}{13}$$
$$-\frac{102}{221}-\frac{39}{221}=\frac{-6}{13}$$
$$\frac{-102-39}{221}=\frac{-6}{13}$$
$$-\frac{141}{221}=\frac{-6}{13}$$
$$-\frac{141}{221}=-\frac{6}{13}$$
$$-\frac{141}{221}=-\frac{102}{221}$$
$$\text{false}$$
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