How to solve 42 - 2/5 = 8

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 42 - 2/5 = 8 | Equatix

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$$\frac { 4 } { 8 } - \frac { 2 } { 5 } =$$

$\frac{1}{10}=0.1$

Reduce the fraction $\frac{4}{8}$ to lowest terms by extracting and canceling out $4$.

$$\frac{1}{2}-\frac{2}{5}$$

Least common multiple of $2$ and $5$ is $10$. Convert $\frac{1}{2}$ and $\frac{2}{5}$ to fractions with denominator $10$.

$$\frac{5}{10}-\frac{4}{10}$$

Since $\frac{5}{10}$ and $\frac{4}{10}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{5-4}{10}$$

Subtract $4$ from $5$ to get $1$.

$$\frac{1}{10}$$

$\frac{1}{2 \cdot 5} = 0.1$