How to solve 4/9 and 48/108

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4/9 and 48/108 | Equatix

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$$\frac { 4 } { 9 } \frac { 48 } { 108 }$$

$\frac{16}{81}\approx 0.197530864$

Reduce the fraction $\frac{48}{108}$ to lowest terms by extracting and canceling out $12$.

$$\frac{4}{9}\times \frac{4}{9}$$

Multiply $\frac{4}{9}$ times $\frac{4}{9}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{4\times 4}{9\times 9}$$

Do the multiplications in the fraction $\frac{4\times 4}{9\times 9}$.

$$\frac{16}{81}$$

$\frac{2 ^ {4}}{3 ^ {4}} = 0.19753086419753085$