$$\frac{4-\sqrt{2}}{7+\sqrt{5}}$$
$\frac{\sqrt{10}+28-4\sqrt{5}-7\sqrt{2}}{44}\approx 0.279966155$
$$\frac{\left(4-\sqrt{2}\right)\left(7-\sqrt{5}\right)}{\left(7+\sqrt{5}\right)\left(7-\sqrt{5}\right)}$$
$$\frac{\left(4-\sqrt{2}\right)\left(7-\sqrt{5}\right)}{7^{2}-\left(\sqrt{5}\right)^{2}}$$
$$\frac{\left(4-\sqrt{2}\right)\left(7-\sqrt{5}\right)}{49-5}$$
$$\frac{\left(4-\sqrt{2}\right)\left(7-\sqrt{5}\right)}{44}$$
$$\frac{28-4\sqrt{5}-7\sqrt{2}+\sqrt{2}\sqrt{5}}{44}$$
$$\frac{28-4\sqrt{5}-7\sqrt{2}+\sqrt{10}}{44}$$
Show Solution
Hide Solution
