How to solve (4(-3)+3)/(6)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (4(-3)+3)/(6) | Equatix

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3(r+2s)=2t-4

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Question

$$\frac{ 4(-3)+3 }{ 6 }$$

Evaluate

$-\frac{3}{2}=-1.5$

Solution Steps

Multiply $4$ and $-3$ to get $-12$.

$$\frac{-12+3}{6}$$

Add $-12$ and $3$ to get $-9$.

$$\frac{-9}{6}$$

Reduce the fraction $\frac{-9}{6}$ to lowest terms by extracting and canceling out $3$.

$$-\frac{3}{2}$$

Show Solution

Factor

$-\frac{3}{2} = -1\frac{1}{2} = -1.5$

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