$$\frac { 4 ^ { 5 } \times a ^ { 8 } b ^ { 3 } } { 4 ^ { 5 } \times a ^ { 8 } b ^ { 2 } }$$
$b$
$$\frac{4^{5}a^{8}b^{3}}{4^{5}a^{8}b^{2}}$$
$$4^{5-5}a^{8-8}b^{3-2}$$
$$4^{0}a^{8-8}b^{3-2}$$
$$a^{8-8}b^{3-2}$$
$$a^{0}b^{3-2}$$
$$b^{3-2}$$
$$a^{0}b^{1}$$
$$a^{0}b$$
$$1b$$
$$b$$
Show Solution
Hide Solution
$1$
$$\frac{\mathrm{d}}{\mathrm{d}b}(b)$$
$$b^{1-1}$$
$$b^{0}$$
$$1$$
