How to solve (41)/(10)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (41)/(10) | Equatix

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Question

$$\frac{ 41 }{ 10 }$$

Evaluate

$\frac{41}{10}=4.1$

Steps For Long Division Method

Use the $1^{st}$ digit $4$ from dividend $41$

$$\begin{array}{l}\phantom{10)}\phantom{1}\\10\overline{)41}\\\end{array}$$

Since $4$ is less than $10$, use the next digit $1$ from dividend $41$ and add $0$ to the quotient

$$\begin{array}{l}\phantom{10)}0\phantom{2}\\10\overline{)41}\\\end{array}$$

Use the $2^{nd}$ digit $1$ from dividend $41$

$$\begin{array}{l}\phantom{10)}0\phantom{3}\\10\overline{)41}\\\end{array}$$

Find closest multiple of $10$ to $41$. We see that $4 \times 10 = 40$ is the nearest. Now subtract $40$ from $41$ to get reminder $1$. Add $4$ to quotient.

$$\begin{array}{l}\phantom{10)}04\phantom{4}\\10\overline{)41}\\\phantom{10)}\underline{\phantom{}40\phantom{}}\\\phantom{10)9}1\\\end{array}$$

Since $1$ is less than $10$, stop the division. The reminder is $1$. The topmost line $04$ is the quotient. Remove all zeros at the start of the quotient to get the actual quotient $4$.

$$\text{Quotient: }4$$ $$\text{Reminder: }1$$

Show Solution

Factor

$\frac{41}{2 \cdot 5} = 4\frac{1}{10} = 4.1$