How to solve (41)/(6)+(14)/(3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (41)/(6)+(14)/(3) | Equatix

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$$\frac{ 41 }{ 6 } + \frac{ 14 }{ 3 }$$

$\frac{23}{2}=11.5$

Least common multiple of $6$ and $3$ is $6$. Convert $\frac{41}{6}$ and $\frac{14}{3}$ to fractions with denominator $6$.

$$\frac{41}{6}+\frac{28}{6}$$

Since $\frac{41}{6}$ and $\frac{28}{6}$ have the same denominator, add them by adding their numerators.

$$\frac{41+28}{6}$$

Add $41$ and $28$ to get $69$.

$$\frac{69}{6}$$

Reduce the fraction $\frac{69}{6}$ to lowest terms by extracting and canceling out $3$.

$$\frac{23}{2}$$

$\frac{23}{2} = 11\frac{1}{2} = 11.5$