Solve (445 + 10p)/(27p) = 15 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac{445+10p}{27p}=15$$

Solve for p

$p = \frac{89}{79} = 1\frac{10}{79} \approx 1.126582278$

Steps for Solving Linear Equation

Variable $p$ cannot be equal to $0$ since division by zero is not defined. Multiply both sides of the equation by $27p$.

$$445+10p=405p$$

Subtract $405p$ from both sides.

$$445+10p-405p=0$$

Combine $10p$ and $-405p$ to get $-395p$.

$$445-395p=0$$

Subtract $445$ from both sides. Anything subtracted from zero gives its negation.

$$-395p=-445$$

Divide both sides by $-395$.

$$p=\frac{-445}{-395}$$

Reduce the fraction $\frac{-445}{-395}$ to lowest terms by extracting and canceling out $-5$.

$$p=\frac{89}{79}$$