How to solve 47/14 - 23/21

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 47/14 - 23/21 | Equatix

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$$\frac{47}{14}-\frac{23}{21}$$

$\frac{95}{42}\approx 2.261904762$

Least common multiple of $14$ and $21$ is $42$. Convert $\frac{47}{14}$ and $\frac{23}{21}$ to fractions with denominator $42$.

$$\frac{141}{42}-\frac{46}{42}$$

Since $\frac{141}{42}$ and $\frac{46}{42}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{141-46}{42}$$

Subtract $46$ from $141$ to get $95$.

$$\frac{95}{42}$$

$\frac{5 \cdot 19}{2 \cdot 3 \cdot 7} = 2\frac{11}{42} = 2.261904761904762$