How to solve 47/3 + 13 = 7

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 47/3 + 13 = 7 | Equatix

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3(r+2s)=2t-4

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Question

$$\frac{47}{3}+13=7$$

Verify

$\text{false}$

Solution Steps

Convert $13$ to fraction $\frac{39}{3}$.

$$\frac{47}{3}+\frac{39}{3}=7$$

Since $\frac{47}{3}$ and $\frac{39}{3}$ have the same denominator, add them by adding their numerators.

$$\frac{47+39}{3}=7$$

Add $47$ and $39$ to get $86$.

$$\frac{86}{3}=7$$

Convert $7$ to fraction $\frac{21}{3}$.

$$\frac{86}{3}=\frac{21}{3}$$

Compare $\frac{86}{3}$ and $\frac{21}{3}$.

$$\text{false}$$

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