How to solve 49/12 - 13/6 =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 49/12 - 13/6 = | Equatix

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$$\frac{49}{12}-\frac{13}{6}=$$

$\frac{23}{12}\approx 1.916666667$

Least common multiple of $12$ and $6$ is $12$. Convert $\frac{49}{12}$ and $\frac{13}{6}$ to fractions with denominator $12$.

$$\frac{49}{12}-\frac{26}{12}$$

Since $\frac{49}{12}$ and $\frac{26}{12}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{49-26}{12}$$

Subtract $26$ from $49$ to get $23$.

$$\frac{23}{12}$$

$\frac{23}{2 ^ {2} \cdot 3} = 1\frac{11}{12} = 1.9166666666666667$