$$\frac{4a-1}{7}=\frac{3a+3}{6}$$
$a=9$
$$6\left(4a-1\right)=7\left(3a+3\right)$$
$$24a-6=7\left(3a+3\right)$$
$$24a-6=21a+21$$
$$24a-6-21a=21$$
$$3a-6=21$$
$$3a=21+6$$
$$3a=27$$
$$a=\frac{27}{3}$$
$$a=9$$
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