$$\frac{4x}{9}+\frac{1}{3}+\frac{13}{108}x=\frac{8x+19}{18}$$
$x=6$
$$12\times 4x+36+13x=6\left(8x+19\right)$$
$$48x+36+13x=6\left(8x+19\right)$$
$$61x+36=6\left(8x+19\right)$$
$$61x+36=48x+114$$
$$61x+36-48x=114$$
$$13x+36=114$$
$$13x=114-36$$
$$13x=78$$
$$x=\frac{78}{13}$$
$$x=6$$
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