$$\frac{ 4x-4 }{ 2 } = \frac{ 3x-6 }{ 3 }$$
$x=0$
$$3\left(4x-4\right)=2\left(3x-6\right)$$
$$12x-12=2\left(3x-6\right)$$
$$12x-12=6x-12$$
$$12x-12-6x=-12$$
$$6x-12=-12$$
$$6x=-12+12$$
$$6x=0$$
$$x=0$$
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