$$\frac{4y+3}{7}+2=\frac{y+5}{2}$$
$y=1$
$$2\left(4y+3\right)+28=7\left(y+5\right)$$
$$8y+6+28=7\left(y+5\right)$$
$$8y+34=7\left(y+5\right)$$
$$8y+34=7y+35$$
$$8y+34-7y=35$$
$$y+34=35$$
$$y=35-34$$
$$y=1$$
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