$$\frac{ 5 }{ 3 } (2y-1)=(3y-5)$$
$y=-10$
$$\frac{5}{3}\times 2y+\frac{5}{3}\left(-1\right)=3y-5$$
$$\frac{5\times 2}{3}y+\frac{5}{3}\left(-1\right)=3y-5$$
$$\frac{10}{3}y+\frac{5}{3}\left(-1\right)=3y-5$$
$$\frac{10}{3}y-\frac{5}{3}=3y-5$$
$$\frac{10}{3}y-\frac{5}{3}-3y=-5$$
$$\frac{1}{3}y-\frac{5}{3}=-5$$
$$\frac{1}{3}y=-5+\frac{5}{3}$$
$$\frac{1}{3}y=-\frac{15}{3}+\frac{5}{3}$$
$$\frac{1}{3}y=\frac{-15+5}{3}$$
$$\frac{1}{3}y=-\frac{10}{3}$$
$$y=-\frac{10}{3}\times 3$$
$$y=-10$$
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