Solve (5)/(3)+(4)/(7)\div(32)/(21) | Equatix

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Question

$$\frac{ 5 }{ 3 } + \frac{ 4 }{ 7 } \div \frac{ 32 }{ 21 }$$

$\frac{49}{24}\approx 2.041666667$

Divide $\frac{4}{7}$ by $\frac{32}{21}$ by multiplying $\frac{4}{7}$ by the reciprocal of $\frac{32}{21}$.

$$\frac{5}{3}+\frac{4}{7}\times \frac{21}{32}$$

Multiply $\frac{4}{7}$ times $\frac{21}{32}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{5}{3}+\frac{4\times 21}{7\times 32}$$

Do the multiplications in the fraction $\frac{4\times 21}{7\times 32}$.

$$\frac{5}{3}+\frac{84}{224}$$

Reduce the fraction $\frac{84}{224}$ to lowest terms by extracting and canceling out $28$.

$$\frac{5}{3}+\frac{3}{8}$$

Least common multiple of $3$ and $8$ is $24$. Convert $\frac{5}{3}$ and $\frac{3}{8}$ to fractions with denominator $24$.

$$\frac{40}{24}+\frac{9}{24}$$

Since $\frac{40}{24}$ and $\frac{9}{24}$ have the same denominator, add them by adding their numerators.

$$\frac{40+9}{24}$$

Add $40$ and $9$ to get $49$.

$$\frac{49}{24}$$

$\frac{7 ^ {2}}{2 ^ {3} \cdot 3} = 2\frac{1}{24} = 2.0416666666666665$