How to solve ( i ) 5/36 + 6/42

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve ( i ) 5/36 + 6/42 | Equatix

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$$\frac { 5 } { 36 } + \frac { 6 } { 42 }$$

$\frac{71}{252}\approx 0.281746032$

Reduce the fraction $\frac{6}{42}$ to lowest terms by extracting and canceling out $6$.

$$\frac{5}{36}+\frac{1}{7}$$

Least common multiple of $36$ and $7$ is $252$. Convert $\frac{5}{36}$ and $\frac{1}{7}$ to fractions with denominator $252$.

$$\frac{35}{252}+\frac{36}{252}$$

Since $\frac{35}{252}$ and $\frac{36}{252}$ have the same denominator, add them by adding their numerators.

$$\frac{35+36}{252}$$

Add $35$ and $36$ to get $71$.

$$\frac{71}{252}$$

$\frac{71}{2 ^ {2} \cdot 3 ^ {2} \cdot 7} = 0.28174603174603174$