How to solve 5/(3x + 1) = 12

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5/(3x + 1) = 12 | Equatix

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$$\frac{5}{3x+1}=12$$

$x=-\frac{7}{36}\approx -0.194444444$

Variable $x$ cannot be equal to $-\frac{1}{3}$ since division by zero is not defined. Multiply both sides of the equation by $3x+1$.

$$5=12\left(3x+1\right)$$

Use the distributive property to multiply $12$ by $3x+1$.

$$5=36x+12$$

Swap sides so that all variable terms are on the left hand side.

$$36x+12=5$$

Subtract $12$ from both sides.

$$36x=5-12$$

Subtract $12$ from $5$ to get $-7$.

$$36x=-7$$

Divide both sides by $36$.

$$x=\frac{-7}{36}$$

Fraction $\frac{-7}{36}$ can be rewritten as $-\frac{7}{36}$ by extracting the negative sign.

$$x=-\frac{7}{36}$$